Python tuples
we are going to be looking at Python Tuples.
Some characteristics of tuples are:
we start by creating a tuple called
“tuple1”.
Notice the type of parenthesis used.
tuple1 = (1, 4, 5, 6)
Here we access the first element of the tuple.
tuple1[0]
Here we access the third element in the tuple.
note that tuple’s are 0 indexed.
tuple1[2]
Here we access the first element and second elements. indexed 0 and 1, but not the third( index 2 is excluded)
tuple1[0:2]
Here we create a copy of the entire tuple using slicing.
tuple1_copy = tuple1[:]
Next we check the length of the tuple1 using the len() function
len(tuple1)
Here we get the max number in the tuple1 using the max() function
max(tuple1)
Here we check for the min number in tuple1 using the min() function
min(tuple1)
Here we create a tuple with one element
tuple2 = ('Ryan', )
here we create an empty tuple
tuple3 = ()
Here, we create tuples of mixed items.
tuple4 = ('Nolan', 1, 1, True)
we cannot modify tuples but we can create a new tuple from existing ones
tuple5 = tuple1 + tuple4
we use the “del” to delete a tuple
del tuple5
Here we create a nested tuple where tuple1 and tuple4 are stored as seperate elements inside tuple6
tuple6 = (tuple1, tuple4)
tuple6
Here, we convert a list to a tuple using the tuple() constructor.
The result is an immutable version of the list
#convert list to tuple
list = [1, 4, 8, 19, 2, 3]
list_tuple = tuple(list)
Here, we extract the values from a dictionary and convert them into a tuple, resulting in “(1,2,3)”
dict = {'a': 1, 'b': 2, 'c': 3}
# Converting dictionary values to a tuple
dict_tuple = tuple(dict.values())
print(dict_tuple)
This creates a new tupple by repeating the contents of tuple2 six times in a row
tuple7 = tuple2 * 6
Here, we check if the value 6 exists in tuple1. it returns True if found otherwise False
6 in tuple1
This checks if the value 8 is absent from tuple1.
It returns True if 8 is not in the tuple.
8 not in tuple1
Here we are comparing two different tuple using various comparism operatrors.
print(tuple1 == tuple2)
print(tuple1 != tuple2)
print(tuple1 < tuple2)
print(tuple1 > tuple2)
print(tuple1 <= tuple2)
print(tuple1 >= tuple2)
We create a tuple of Cricket players
Cricket_Players = ('Bradman','Trumper','Hobbs', 'Ranji')
Next we loop through the cricket players by itertng over it.
for Cricketer in Cricket_Players:
print(Cricketer)
This line unpacks the Cricket_Players tuple into four separate variables: Cricketer_1 to Cricketer_4, each holding one value from the tuple.
Cricketer_1, Cricketer_2, Cricketer_3, Cricketer_4 = Cricket_Players
Here we create another tuple called “tuple8”
tuple8 = (3, 6, 8, 1, 5, 2)
Using the sort() function, we sort the tuple8
sorted(tuple8)
This returns a new list with the elements of tuple8 sorted in descending order( largest to smallest)
sorted(tuple8, reverse=True)
We create another tuple called “tuple9”
tuple9 = (1, 2, 3, 1, 1)
Next we attempt to modify the tuple. This would result in an error
tuple9[0] = 1
This prints the number of times the value “1” appears in the uple “tuple9”
print(tuple9.count(1))
This returns the index of the first occurrence of the value 2 in tuple9
print(tuple9.index(2))
Tbis function calculates and returns both the area and perimeter of a square based on the given length
def square_calcs(length):
area = length * length
perimeter = 4 * length
return area, perimeter
This calls the square_calcs function with 5 as the length
result = square_calcs(5)
This accesses the area from the results tuple retuned by square_calcs(5)
result[0]
This retrieves the perimeter from the result tuple returned by square_calc(5)
result[1]
Here, we unpack the result tuple into two seperate variables “area” and “perimeter”.
area, perimeter = result
area
perimeter
